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the zero of H(z) is inside the unit circle, and H(z) is minimum phase. regardless of whether the zero of G(z) is inside or outside the unit circle. Let us now look at the least-squares inverse, hN(n), length N . In this case, the linear equations have the form of'

Reasons Given Opposite sides of a parallelogram are parallel. Alternate interior angles of parallel lines are congruent. Vertical angles are congruent. Two triangles are similar if two angles of one triangle are congruent to two angles of the other. 6. Corresponding sides of similar triangles are in proportion.

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Solving these equations for arbitrary a and N may be accomplished as follows. For n = 1.2, . . . , N - 2 these equations may be represented by the homogeneous difference equation,

PRINCIPLE 1: PRINCIPLE 2: PRINCIPLE 3:

where c l and c.2 are constants that are determined by the boundary conditions at 11 = O and n = N last equations in Eq. (9.22)l:

m. If Ial < 1,

2.1 THE COORDINATES OF A POINT We shall establish a correspondence between the points of a plane and pairs of real numbers. Choose two perpendicular lines in the plane of Fig. 2-1. Let us assume for the sake of simplicity that one of the lines is horizontal and the other vertical. The horizontal line will be called the x-axis and the vertical line will be called the y-axis.

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Corresponding sides of similar triangles are in proportion. Corresponding segments of similar triangles are in proportion. Corresponding segments of similar polygons are in proportion.

lirn h N ( n )= -- a"

When segments replaces sides, Principle 1 becomes the more general Principle 2. When polygons replaces triangles, Principle 2 becomes the even more general Principle 3. By segments we mean straight or curved segments such as altitudes, medians, angle bisectors, radii of inscribed or circumscribed circles, and circumferences of inscribed or circumscribed circles. The ratio of similitude of two similar polygons is the ratio of any pair of corresponding lines. Corollaries of Principles 2 and 3, such as the following, can be devised for any combination of corresponding lines: 1. Corresponding altitudes of similar triangles have the same ratio as any two correponding medians.

-I\'

Fig. 7-22

which is the inverse filter, that is,

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Fig. 2-1 Next choose a coordinate system on the x-axis and one on the y-axis. The origin for both coordinate systems is taken to be the point O, where the axes intersect. The x-axis is directed from left to right, the y-axis from bottom to top. The part of the x-axis with positive coordinates is called the positive x-axis, and the part of the y-axis with positive coordinates the positive y-axis. Consider any point P in the plane. Take the vertical line through the point P, and let a be the coordinate of the point where the line intersects the x-axis. This number a is called the x-coordinate of P (or the abscissa of P). Now take the horizontal line through P, and let b be the coordinate of the point where the line intersects the y-axis.

Fig. 7-23

lim h N ( n )= a n u ( n )= g - l ( n )

lirn H N ( z )= I - az-'

7.26 Line ratios from similar triangles (a) In two similar triangles, corresponding sides are in the ratio 3:2. Find the ratio of corresponding medians [see Fig. 7-24(a)]. (b) The sides of a triangle are 4, 6, and 7 [Fig. 7-24(b)]. If the perimeter of a similar triangle is 51, find its longest side. (c) In nABC of Fig. 7-24(c), BC 25 and the measure of the altitude to BC is 10. A line segment terminating in the sides of the triangle is parallel to BC and 3 units from A. Find its length.

> 1,

Fig. 7-24

lirn h N ( n )= -= a-n-2

CHAP. 2]

(a) If nABC , nA B C and s sr m 3 , then 2 mr 6 7 3 . 2 17. Since nABC , nA B C , 71. 2 s 7 51 and s 17 21.

@N+ a -2 1

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